39 lines
594 B
Markdown
39 lines
594 B
Markdown
---
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title: leetcode-1160
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date: 2020-04-01 00:18:48
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tags:
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categories: leetcode
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---
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### 1160. 拼写单词
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[题目](https://leetcode-cn.com/problems/find-words-that-can-be-formed-by-characters/)
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<!--more-->
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利用列表 remove 方法，检查 chars 中是否有足够的字母拼写 word
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```python
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class Solution:
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def countCharacters(self, words, chars: str) -> int:
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words_ = ''
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for w in words:
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lchars = list(chars)
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try:
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for l in w:
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lchars.remove(l)
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except:
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continue
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words_ += w
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return len(words_)
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# 152 ms 14.1 MB
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```
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