10 lines
5.5 KiB
HTML
10 lines
5.5 KiB
HTML
<!DOCTYPE html><html lang="zh-CN"><head><meta charset="utf-8"><meta name="X-UA-Compatible" content="IE=edge"><title> leetcode-914 · MarkDown</title><meta name="description" content="leetcode-914 - Ching"><meta name="viewport" content="width=device-width, initial-scale=1"><link rel="short icon" href="/favicon.png"><link rel="stylesheet" href="/css/apollo.css"><link rel="stylesheet" href="https://fonts.googleapis.com/css?family=Source+Sans+Pro:400,600" type="text/css"><meta name="generator" content="Hexo 6.0.0"><link rel="alternate" href="/atom.xml" title="MarkDown" type="application/atom+xml">
|
||
</head><body><header><a href="/" class="logo-link"><img src="/logo.png"></a><ul class="nav nav-list"><li class="nav-list-item"><a href="/" target="_self" class="nav-list-link">ALL</a></li><li class="nav-list-item"><a href="/categories/leetcode/" target="_self" class="nav-list-link">LEETCODE</a></li><li class="nav-list-item"><a href="/atom.xml" target="_self" class="nav-list-link">RSS</a></li></ul></header><section class="container"><div class="post"><article class="post-block"><h1 class="post-title">leetcode-914</h1><div class="post-meta"><div class="post-time">2020年3月29日</div></div><div class="post-content"><h3 id="914-卡牌分组"><a href="#914-卡牌分组" class="headerlink" title="914. 卡牌分组"></a>914. 卡牌分组</h3><p><a target="_blank" rel="noopener" href="https://leetcode-cn.com/problems/x-of-a-kind-in-a-deck-of-cards/">题目</a></p>
|
||
<span id="more"></span>
|
||
|
||
|
||
|
||
<p>将大牌堆分成多个牌数量相等的小牌堆,就是求每张牌数量的公约数。先遍历一遍得到每张牌的数量,然后找出比2大的公约数即可。</p>
|
||
<figure class="highlight python"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br><span class="line">9</span><br><span class="line">10</span><br><span class="line">11</span><br><span class="line">12</span><br><span class="line">13</span><br><span class="line">14</span><br><span class="line">15</span><br><span class="line">16</span><br><span class="line">17</span><br><span class="line">18</span><br><span class="line">19</span><br><span class="line">20</span><br><span class="line">21</span><br><span class="line">22</span><br><span class="line">23</span><br><span class="line">24</span><br><span class="line">25</span><br><span class="line">26</span><br><span class="line">27</span><br></pre></td><td class="code"><pre><span class="line"><span class="class"><span class="keyword">class</span> <span class="title">Solution</span>:</span></span><br><span class="line"> <span class="function"><span class="keyword">def</span> <span class="title">hasGroupsSizeX</span>(<span class="params">self, deck</span>) -> <span class="built_in">bool</span>:</span></span><br><span class="line"> dc = {}</span><br><span class="line"> max_d = <span class="number">0</span></span><br><span class="line"> <span class="keyword">for</span> d <span class="keyword">in</span> deck:</span><br><span class="line"> <span class="keyword">if</span> d <span class="keyword">not</span> <span class="keyword">in</span> dc:</span><br><span class="line"> dc[d] = <span class="number">0</span></span><br><span class="line"> dc[d] += <span class="number">1</span></span><br><span class="line"> <span class="keyword">if</span> max_d < d:</span><br><span class="line"> max_d = d</span><br><span class="line"> <span class="keyword">if</span> max_d < dc[d]:</span><br><span class="line"> max_d = dc[d]</span><br><span class="line"> has_x = <span class="literal">True</span></span><br><span class="line"> <span class="keyword">if</span> max_d == <span class="number">1</span>:</span><br><span class="line"> max_d = <span class="number">2</span></span><br><span class="line"></span><br><span class="line"> <span class="keyword">for</span> i <span class="keyword">in</span> <span class="built_in">range</span>(<span class="number">2</span>, max_d + <span class="number">1</span>):</span><br><span class="line"> has_x = <span class="literal">True</span></span><br><span class="line"> <span class="keyword">for</span> k,v <span class="keyword">in</span> dc.items():</span><br><span class="line"> <span class="keyword">if</span> v % i:</span><br><span class="line"> has_x = <span class="literal">False</span></span><br><span class="line"> <span class="keyword">break</span></span><br><span class="line"> <span class="keyword">if</span> has_x <span class="keyword">and</span> i >= <span class="number">2</span>:</span><br><span class="line"> <span class="keyword">return</span> <span class="literal">True</span></span><br><span class="line"> <span class="keyword">return</span> <span class="literal">False</span></span><br><span class="line"></span><br><span class="line"><span class="comment">#56 ms 13.8 MB</span></span><br></pre></td></tr></table></figure>
|
||
|
||
</div></article></div></section><footer><div class="paginator"><a href="/2020/03/30/leetcode-999/" class="prev">PRVE</a><a href="/2020/03/29/leetcode-1013/" class="next">NEXT</a></div><div class="copyright"><p>© 2016 - 2022 <a href="http://blog.tunpok.com">Ching</a>, unless otherwise noted.</p></div></footer><script src="https://cdn.bootcss.com/mathjax/2.5.3/MathJax.js?config=TeX-AMS-MML_HTMLorMML"></script></body></html> |