836. 矩形重叠
题目
看两个矩形有没有重叠，就看两个矩形在坐标轴上的投影有没有重叠。
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| class Solution:
def isRectangleOverlap(self, rec1, rec2) -> bool:
return ((min(rec1[2], rec2[2]) > max(rec1[0], rec2[0]))
and (min(rec1[3], rec2[3]) > max(rec1[1], rec2[1])))
s = Solution()
s.isRectangleOverlap(rec1 = [0,0,2,2], rec2 = [1,1,3,3])
|
